Partial Molar Properties And Their Application

Partial Molar Properties And Their Application Thermodynamics deals with energy changes and its relationship with work. It is based on three laws of thermodynamics which are used as axioms just as Newtons laws motion from the basis of classical mechanics. The first two laws are based on facts observed in every day life. The predictions based on these laws have been verified in most cases and so far no case has been reported where the laws break down. The laws can be stated in mathematical form. Hence, thermodynamics is an exact science. The thermodynamic theory can be developed without gaps in the argument using only moderate knowledge of mathematics. [B.]ABOUT PARTIAL MOLAR PROPERTY: Thermodynamic relations derived earlier are applicable to closed systems. In a system where not only the work and heat but also several kinds of matter are being exchanged, a multicomponent open system has to be considered. Here, the amounts of the various substances are treated as variables like any other thermodynamic variables. For example, the gibbs free energy of a system is a function not only of temperature and pressure , but also of the amount of each substance in the system,such that G=f(T,p,n1,n2à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦.nk) Where n1,n2,à ¢Ã¢â€š ¬Ã‚ ¦.,nk represent the amounts of each of the K components in the system . for simplicity, let a system contain only two components. The total differential of G is dG=(?G/?T)P,n1,n2 dT+(?G/?p)T,n1,n2 dp+(?G/?n1)T,p,n2 dn+(?G/?n2)T,p,n1 dn2 In this eq., the partial derivatives (?G/?n1)T,P,n2 and (?G/?n2)T,P,n1 are known as partial molar free energies of components one and two , respectively. In genral, the partial derivative of a thermodynamic function Y with respect to the amount of component i of a mixture when T,p and amounts of other constituents are kept constant , is known as the partial molar property of the ith component and is represented as Yi,pm. Thus Yi,pm=(?Y/?ni)T,p,njs i=!j [C.]DEFINITION OF PARTIAL MOLAR PROPERTY: The partial molar property may be defined in either of the following two ways: 1. it is the change in Y when 1 mole of component i is added to a system which is so large that this addition has a negligible effect on the composition of the system. 2. Let dY be the change in value of Y when an infinitesimal amount dni of component i is added to a sysem of definite composition. By an infinitesimal amount dni we mean that its addition does not cause any appreciable change in the composition of the system. If we divide dY by dni , we get the partial molar property (?Y/?ni). thus, the partial molar property of the component i may be defined as the change in Y per mole of component i when an infinitesimal amount of this component is added to a system of definite composition. [D.]TYPES OF MOLAR PROPERTIES: (a.) Partial molar volume: The partial molar volume is broadly understood as the contribution that a component of a mixture makes to the overall volume of the solution. However, there is rather more to it than this: When one mole of water is added to a large volume of water at 25 °C, the volume increases by 18cm3. The molar volume of pure water would thus be reported as 18cm3 mol-1. However, addition of one mole of water to a large volume of pure ethanol results in an increase in volume of only 14cm3. The reason that the increase is different is that the volume occupied by a given number of water molecules depends upon the identity of the surrounding molecules. The value 14cm3 is said to be the partial molar volume of water in ethanol. In general, the partial molar volume of a substance X in a mixture is the change in volume per mole of X added to the mixture. The partial molar volumes of the components of a mixture vary with the composition of the mixture, because the environment of the molecules in the mixture changes with the composition. It is the changing molecular environment (and the consequent alteration of the interactions between molecules) that results in the thermodynamic properties of a mixture changing as its composition is altered. The partial molar volume, VJ, of any substance J at a general composition, is defined as: Fig: the partial molar volumes of water and ethanol at 25degree C where the subscript n indicates that the amount of all the other substances is held constant. The partial molar is the slope of the plot of the total volume as the amount of J is changed with all other variables held constant: Note that it is quite possible for the partial molar volume to be negative, as it would be at II in the above diagram. For example, the partial molar volume of magnesium sulphate in water is -1.4cm3 mol-1. i.e. addition of 1 mol MgSO4 to a large volume of water results in a decrease in volume of 1.4 cm3. (The contraction occurs because the salt breaks up the open structure of water as the ions become hydrated.) Once the partial molar volumes of the two components of a mixture at the composition and temperature of interest are known, the total volume of the mixture can be calculated from: The expression may be extended in an analogous fashion to mixtures with any number of components. The most common method of measuring partial molar volumes is to measure the dependence of the volume of a solution upon its composition. The observed volume can then be fitted to a function of the composition (usually using a computer), and the slope of this function can be determined at any composition of interest by differentiation. (b.) Partial molar gibbs energies: The concept of a partial molar quantity can be extended to any extensive state function. For a substance in a mixture, the chemical potential is a defined as the partial molar gibbs energy: i.e. the chemical potential is the slope of a plot of the Gibbs energy of the mixture against the amount of component J, with all other variables held constant: In the above plot, the partial molar Gibbs energy is greater at I than at II. The total Gibbs energy of a binary mixture is given by: The above expression may be generalised quite trivially to a mixture with an arbitrary number of components: where the sum is across all the different substances present in the mixture, and the chemical potentials are those at the composition of the mixture. This indicates that the chemical potential of a substance in a mixture is the contribution that substance makes to the total Gibbs energy of the mixture. In general, the Gibbs energy depends upon the composition, pressure and temperature. Thus G may change when any of these variables alter, so for a system that has components A, B, etc, it is possible to rewrite the equation dG = Vdp SdT (which is a general result that was derived here) as follows: which is called the fundamental equation of chemical thermodynamics. At constant temperature and pressure, the equation simplifies to: Under these conditions, dG = dwn,max (as was demonstrated here), where the n indicates that the work is non-expansion work. Therefore, at constant temperature and pressure: The idea that the changing composition of a system can do work should be familiar this is what happens in an electrochemical cell, where the two halves of the chemical reaction are separated in space (at the two electrodes) and the changing composition results in the motion of electrons through a circuit, which can be used to do electrical work. On a final note, it is possible to use the relationships between G and H, and G and U, to generate the following relations: Note particularly the conditions (the variables that must be held constant) under which each relation applies. Fig: the partial molar volumes of water and ethanol at 25degree C where the subscript n indicates that the amount of all the other substances is held constant. The partial molar is the slope of the plot of the total volume as the amount of J is changed with all other variables held constant: Note that it is quite possible for the partial molar volume to be negative, as it would be at II in the above diagram. For example, the partial molar volume of magnesium sulphate in water is -1.4cm3 mol-1. i.e. addition of 1 mol MgSO4 to a large volume of water results in a decrease in volume of 1.4 cm3. (The contraction occurs because the salt breaks up the open structure of water as the ions become hydrated.) Once the partial molar volumes of the two components of a mixture at the composition and temperature of interest are known, the total volume of the mixture can be calculated from: The expression may be extended in an analogous fashion to mixtures with any number of components. The most common method of measuring partial molar volumes is to measure the dependence of the volume of a solution upon its composition. The observed volume can then be fitted to a function of the composition (usually using a computer), and the slope of this function can be determined at any composition of interest by differentiation. (C.)PARTIAL MOLAR THERMAL PROPERTIES: 1. Partial molar heat capacities: the heat capacity at constant pressure Cp of a solution containing n1 moles of solvent and n2 moles of solute is given by Cp=(?H/?T)P,N à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦eq(1) The pressure and compostion being constant. Upon differentiation with respect to n1,maintaining n2 constant,it follows that CP1=(?CP/?n1)T,P,n2 =?H/?T?n1 .eq(2) Where Cp1 is the partial molar heat capacity,at constant pressure,of the constituent 1 of the given solution. The partial molar heat constant H1 of this constituent is defined by H1=(?H/?n1)T,P,n2 And hence differentiation with respect to temp. gives (?H1/?T)P,N=?H/?T?n1 =CP1 à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦.eq(3) The result being identical with CP1 by eq.(3). The partial molar heat capacity of the solvent is any particular solution thus be defined by either eq(1) and eq(2). Similarly,i.e.,constituent 2, Cp2=(?CP/?n2)T,P,n1 =(?H2/?T)P,N à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦..eq(4) We know, Li=H1-H10 Is differentiated with respect to temp.,at constant pressure and composition,it follows that (?L1/?T)P,N=(?H1/?T)P,N-(?H10/?T)P,N = Cp1-Cp10 à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦eq(5) Where Cp1,identical with Cp1 or Cp1o, is the molar heat capacity of the pure solvent or the partial molar heat capacity of the solvent in a solution at infinite dilution. Thus, Cp10 may be regarded as an experimental quantity, and if the variation of the relative partial molar heat content of the solvent with temperature,i.e. (?L1/?T)P,N, is known , it is possible to determine Cp1 at the corresponding composition of the solution. The necessary data are rarely available from direct thermal measurements of L1, such as thus described in 44f,at several temperatures, but the information can often be obtained, although not very accurately from E.M.F measurements. By differentiating the expression for the relative partial molar heat content of the solute it is found, in an exactly similar manner to that used above , that (?L2/?T)P,N=(?H2/?T)P,N-(?H02/?T)P,N =CP2-CP20 à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦eq(6) In this expression,Cp20 is the partial molar heat capacity of the solute in the infinitely dilute solution. Although the experimentel significance of the quantity is not immediately obvious.thus from a knowledge of the variation of L2, the partial molar heat content of the solute with temprature it should be possible to derive, with the aid of equation(6) , the partial molar heat capacity of the solute Cp2 at the given composition. [E.]Determination of partial molar properties: 1.Direct method: in view of the definition of the partial molar properties Gi as Gi=(?G/?ni)T,P,n1,à ¢Ã¢â€š ¬Ã‚ ¦.. à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦.eq(1) An obvious method ffor its determination is to plot the value of the extensive properties G,at constant temperature and pressure, for various mixtures of the two components against the number of moles,e.g.,n2,of the one of them,the value of n1 being kept constant. The slope of the curve at any particular composition,which maybe determined by drawing a tengent to the curve, gives the value of G2 at that comoposition. Since the molality of a solution represents the number of moles of solute associated with a constant mass,and hence a constant number of moles,the plot of the property G against the molality can be used for the evaluation of the partial molar property of the solute. Once G2 at any composition has been determined, the corresponding value of G1 is readily derived by means of the relationship, G=n1G1+n2G2 In view of the difficulty of determining the exact slope of the curve at all points, it is preferable to use an analytical procedure instead of the graphical one just described. The property G is then expressed as a function of the number of moles of one component,e.g.,the molality, associated with a constant amount of the other component. Upon differentiation with respect to n,i.g.,the molality, an expression for the partial molar property is obtained. 2.from apparent molar properties: a method that is often more convenient and accuarate than that described above,makes use of the apparent molar property. We know G-n1G1=n2à ¶2 If n1 is maintained constant,so that n1G1 is constant, differentiation with respect to n2 , constant temp. and pressure being understood,gives G2 =(?G/?n2)n1 = (?à ¶G/?n2)n1 + à ¶G à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦eq(2) G2 = ((?à ¶G/? ln n2)n1+ à ¶G à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦..eq(3) Since the molality m is equivalent to n2, with n1 constant, eq(2) and eq(3) may be written as G2= m (d à ¶G/dm)+ à ¶G à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦eq(4) G2=( d à ¶G/d ln m)+ à ¶G à ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦Ãƒ ¢Ã¢â€š ¬Ã‚ ¦..eq(5) Respectively. If the apparent molar property à ¶G is determined for various values of n2 , with n1 constant , or at various molalities, the partial molar property G2 can be calculated from the slope, at any given composition, of the plot of à ¶G against n2 or against ln n2. The method based on the use of eqs(3)(5) is usally more accurate than that involving the logarithmic plot,since it does not give undue importance to result obtained in dilute solutions. An analytical method can, of course, be used in place of the graphical procedure if à ¶G can be expressed as a function of n2 or of the molality. For use in a later connection, an alternative form of eq(4) is required and it will be derived here. The right hand side of this equation is equivalent to d(m à ¶G)/dm, that is, m (d à ¶G/dm)= G2 and upon integration, m varying between the limits of zero and m, and mdà ¶G between zero and mà ¶G, it is found that mà ¶G=?0m G2 dm à ¶G=1/m?0m G2 dm for dilute solutions,the molality is proportional to the molar concentration c, and hence it is permissible to put this result in the form à ¶G=1/c?0m G2 dm [F.] APPLICATION OF PARTIAL MOLAR PROPERTIES: These properties are very useful since each and every reaction in chemistry occurs at a constant temperature and pressure and under these conditions we can determine these with the help of partial molar properties. They are highly useful when specific properties of pure substances and properties of mixing are considered. By definition, properties of mixing are related to those of the pure substance by: Here * denotes the pure substance M the mixing property z corresponds to the specific property From the definition of partial molar properties, substitution yields: Hence if we know the partial molar properties we can derive the properties of mixing.For the internal energy U, enthalpy H, Helmholtz free energy A, and Gibbs free energy G, the following hold: whereP is the pressure V is the volume T is temperature S is the entropy [G.] BIBLIOGRAPHY: 1. THERMODYNAMICS AND CHEMICAL EQUILIBRIUM AUTHOR: K L KAPOOR 2. THERMODYNAMICS FOR CHEMISTS AUTHOR: SAMUEL GLASSTONE 3. http://www.everyscience.com/Chemistry/Physical/Mixtures/a.1265.php 4. http://www.everyscience.com/Chemistry/Physical/Mixtures/b.1266.php 5. http://www.chem.ntnu.no/nonequilibrium-thermodynamics/pub/192-Inzoli-etal.pdf 6. http://physics.about.com/od/thermodynamics/p/thermodynamics.htm 7. http://www.chem.boun.edu.tr/webpages/courses/chem356/EXP5-Determination%20of%20Partial%20Molar%20Quantities.pdf

Fate in Medea Essay -- Classics Medea Greek Essays

Observation and Interpretation: Throughout the text, fate and the gods are blamed for the cause of the problems, however subsequent choices made later on by the characters appear to be free will, however are actually influenced by fate and the gods. So what?: This makes the audience blame the gods for the overall out come, but still blame the main character for her choices. Quotes: P48 l. 1014-1015 â€Å"The gods/ And my evil-hearted plots have led to this.† P39 l. 717 â€Å"What good luck chance has brought you.† P61 l. 1416-1419 â€Å"Many matters the gods bring to surprising ends./ The things we thought would happen do not happen;/ The unexpected God makes possible;/ And such is the conclusion of this story.† To an ancient Greek, fate was thought of as the power that determined all of our destinies, although a person could make choices along their life to change small outcomes, which was the extent of free will. In the play Medea, fate is used as a scapegoat to blame some of the problems happening to the characters, despite the fact that most of the characters had free will. In some instances the characters are not even aware of the causes behind the causes of their problems. Therefore, throughout the text, fate and the gods are blamed for the cause of the problems, however subsequent choices made later on by the characters appear to be free will, however are actually influenced by fate and the gods. The characters in the play make many references to...

The Short-term Significance of the Cuban Missile Crisis between the US

The event of the Cuban Missile Crisis of October 1962 was the closest the world has ever come to nuclear war. Fifteen years into the cold war, the two superpowers continued the fierce competition to increase their military strength. In 1962, the Soviet Union was desperately behind the United States in the nuclear arms race. Soviet missiles were only powerful enough to be launched against Europe, whereas the US missiles were capable of striking the entire Soviet Union. In late April 1962, Soviet Premier Nikita Khrushchev conceived the idea of placing intermediate-range missiles in Cuba which would double the Soviet strategic arsenal and provide a real deterrent to a potential U.S. attack against the Soviet Union. The fate of millions literally hinged upon the ability of two men, President John F. Kennedy and Premier Nikita Khrushchev, to reach a compromise. The sources I have researched strongly agree that it was President Kennedy who was very determined to prevent the world from anot her war. They also show that the crisis was not just a conflict about missiles; it was a conflict of contradictory philosophies, ideologies and power. John F. Kennedy, the newly chosen American president, and the Soviet premier met in Vienna to discuss the east-west confrontation, in particular, the situation in Berlin over the Berlin Wall. They resolved nothing, and Khrushchev left the June 1961 summit thinking Kennedy was a weak president. This could have been the point where Khrushchev thought he could overcome Kennedy and, therefore, make his pathway towards gaining the world power. His first major task was, therefore, to bond with Fidel Castro. Cuban President Fidel Castro was looking for a way to defend his nation from an attack by the U.S. Eve... ... like the ones based in Cuba. Find in: Primary Sources 4. Tompson 1995, p. 248. 5. â€Å"Political Cartoon.† 1962. Google Images. This is a cartoon showing the struggle between Kennedy and Khrushchev. Find in: Primary sources 6. The Washington Post article â€Å"Soviets Knew Date of Cuba Attack†. Find in: Primary Sources 7. Letter: Khrushchev to Kennedy, 26 October 1962. Find in: Primary Sources 8. Letter: Khrushchev to Kennedy, 28 October 1962. Find in: Primary Sources 9. Letter: Kennedy to Khrushchev, 27 October 1962. Find in: Primary Sources 1. Tompson, William J. (1995), Khrushchev: A Political Life, St. Martin's Press, ISBN 0-312-12365-5 2. Kellner, Douglas (1989). Ernesto "Che" Guevara (World Leaders Past & Present). Chelsea House Publishers. pp. 112. ISBN 1555468357. 3. http://history.utah.gov/historical_society/history_fair/documents/2008CubanMissilepaper.pdf

drug essay :: essays research papers

Would I say no to drugs and alcohol if I were asked to try it? That is a question that I have been asked many times. What else can I say but absolutely! Why would I say yes to something that very slowly destroys your body? Frankly, I don’t know why anybody would actually want to try it if they know the consequences that they will end up with later in life. Everybody knows, you and I know it, that if they continue smoking for the rest of their life, it is just a matter of time until something really horrible rolls around the corner and ruins the rest of their life. Just think of all the great opportunities that would be waiting for them if they chose to live a healthy life. Have you ever seen those smoking commercials? For instance, the one with the old lady with the hole in her neck? Well, some people might think those commercials are just pointless and gross, but I have a different opinion. I think those commercials send a strong message to young kids just starting to experiment with booze and drugs. They can see the actual effects they have on people and maybe, just maybe, teenagers and other people who are just starting will think twice about making smoking a regular habit. Bad breath, premature wrinkles, yellow teeth, etc. are just some of the short-term effects that drugs will cast upon you. It’s almost like casting a spell on you†¦Ã¢â‚¬ ¦magically they just appear. Some long-term effects of the poisons are much more severe and if you are lucky enough to receive them, you’ll sure wish you never started. Cancer, emphysema, and birth defects if you are pregnant, are just some of the horrible long-term effects that you will probably end up with in the latter parts of your life.

Latvia and Great

Due today : Outline the answers to the following questions: Thesis: Before Peter the Great, Russia was more of an Asian nation than a European nation. A. Give one argument to support this statement B. Bullet two ways by which Peter the Great tried to westernize Russia C. Name one territory he gained for Russia D. Explain one reason why Catherine the Great was interested in extending her empire to the Black Sea. A. Before Peter the Great, Russia was more of an Asian nation than a European nation. a. i. Before Peter the Great, no Russian had the courage to even try to convertRussia into an westernized, European nation. When Peter the Great acquired power, he improved the Russian army, remodeled the social and economic structure of Russia and conquered territory towards Sweden to gain access to the Baltic Sea. B. Peter the Great tried to westernize Russia by: a. i. Applying European culture, including: clothing and life style and even forcing men to shave their long beards. a. ii. Impro ving: industry, military, housing, trading, manufacturing and agriculture by more taxes. C. Peter the Great gained many territories from 1700 to 1721.Peter the Great led Russia in a war against Sweden. From this war, Russia gained control over territory along the eastern shores of the Baltic Sea. This land gave Russia a direct approach by water to the rest of Europe. Peter attacked Persia and conquered territory along the Caspian Sea. These conquests helped Russia to expand its trade with other countries. D. Catherine the Great was interested in extending her empire towards the Black Sea because: a. i. She wanted to continue the expansionist policies of Peter the Great and conquer the black sea in order to please Russia's demands of sought warm ports.

Assignment #2 †Zale Jewelers Flop at the High End Essay

1.What do you imagine go issue be the effectiveness of Burton locomote Zales Jewelers to its regular melody system? In your answer, define or categorize that strategy.I appreciate that Burton returning the Zales Jewelers to its regular championship strategy leave bring binding off the comp whatever from the decline it was facing with specialness as CEO. The business strategy trashy had in mind was cutting the customers Zales had tremendously. For geezerhood Zales has always been seen a specific instigant with focus on baseball field peal and jewelry and their customers go to them beca example of that. Bringing covering Zales to its regular business strategy exit servicing in terms of the operational effectiveness. They willing be able to sell their increases value. Burton will use a business-level strategy which will focus on product differentiation, focus and cost principalership. This strategy will help the alliance get back from the Fortes disaster of a s trategy.The product differentiation will qualifying products to customers that cannot be found in any of their competitors stores. Having unique diamond jewelry and being able to hand it will attract new and sexagenarian Zales customers. Focus strategy focuses on a specific buyer securities industry. Knowing your label and who your intended focus will be on is important for a party. When I hear Zales I get images of diamonds, competitiveness rings, and jewelry. Focusing on these points will help the business strategy. Lastly, cost leadership is providing a product at a lowly cost which will give the company a gain in market share.Zales cuts prices on holidays which bring in much business and helps in terms of their suppliers. I theorise that bringing back Zales to how it use to be, to the diamond store everyone knows it to be will drive sales up. Once the business strategy is properly thought out where they know what key areas to focus on they will have no problems in term s of appeal to customers.2.What should Burton do well-nigh the ethical and legal problems facing Zales?Burton should receive care of the ethical and legal problems facingI think that Burton should use the functional-level strategy where you find and go on the best people. Legal problems can lead a company down the legal injury road and potentially injure them financially. respectable behavior within a company is very important. It could be the difference mingled with a company being sure-fire and getting sued. As for Burton I think that she should first focus on purpose a highly competent person that will behave ethically. Also she should follow through new and stricter policies, procedures and rules everyone (even high level executives) should follow. The policies will

Memorandum – for Hospitality

Memorandum To Kitchen Operations Staff From humans Resources Date 30th February 2013 Subject Prevention of nutrition poisoning. This memo is intended to inform and update employees on the clip practices in the kitchen that are important in the measure of food for thought poisoning. Employees are expected to postulate a clear understanding of The Food make for 2003(NSW) and Food Regulations 2004(NSW). A copy of the Act is ready(prenominal) with your supervisor for reference. Food handlers are wakelessly obligate to follow these requirements. Please en authoritative a HACCP make is followed during the production of food.Periodic checks and audits from internal and external teams are indispensable to ascertain proper HACCP processes are followed. (It should be celebrated that HACCP process is a legal obligation for food handlers). Employees must maintain proper personal hygiene. This is comprehensive of some golden rules much(prenominal) as great personal grooming, treati ng cuts and wounds and washing hands regularly. Personal health issues that pose a risk in the study (food borne/airborne diseases, illnesses such as influenza or infections from open cuts/wounds) should be treated as shortly as possible.Food conceptualization procedures include proper precaution of the food preparation areas and food service areas. circumstance care must be taken to the sink hand washing technique and the usage of gloves when intervention food. Safe food storage is a legal obligation. Goods should be stored according to the manufacturers instruction, temperature controlled , properly packed and labelled, checked for expiration, follow stock rotation, forfend storing chemicals in old containers and store substances in screen out well-lit and ventilated storerooms.Ensure that the bins are sanitised and emptied regularly. Be sure to categorise the waste storage area so that waste and recyclable items are separated. Objects and areas such as work benches , u tensils , dinnerware and glassware should be cleaned and sanitised good to prevent contamination. Regular checks to be done on temperature controlled equipment. Maintaining temperature is an important aspect of food preservation.Any malfunction of these equipment should be immediately reported and rectified. all of the above if not followed can cause food contamination which could maybe lead to Food poisoning which broadly fall under Chemical (caused by the presence of chemicals such as cleaning agents ), Biological (harmful bacteria that is make on food due to food despoilation from incorrect preservation of food) or Physical ( caused by glass fragments or metal shavings from incorrect preparation process) food poisoning.Signed, General Manager Human Resources Riya Jude __________________________________________________________________________________ All employees must read this memo and sign the firmness of purpose below I read and understood the work practices in the kitc hen that are important in the prevention of food poisoning. Name Signature Date